Base | Representation |
---|---|
bin | 11001001111100100100100… |
… | …011000110100010111010100 |
3 | 112120002112011201100222212020 |
4 | 121033210210120310113110 |
5 | 104022432424322320040 |
6 | 1032042235555053140 |
7 | 32246006221356660 |
oct | 3117444430642724 |
9 | 476075151328766 |
10 | 111021220120020 |
11 | 32413920493361 |
12 | 105507a5ba11b0 |
13 | 49c4343962022 |
14 | 1d5b6547198a0 |
15 | cc7db3da6cd0 |
hex | 64f9246345d4 |
111021220120020 has 384 divisors, whose sum is σ = 401541223587840. Its totient is φ = 22307841884160.
The previous prime is 111021220119989. The next prime is 111021220120061. The reversal of 111021220120020 is 20021022120111.
It is a super-2 number, since 2×1110212201200202 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3868632 + ... + 15395088.
It is an arithmetic number, because the mean of its divisors is an integer number (1045680269760).
Almost surely, 2111021220120020 is an apocalyptic number.
111021220120020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111021220120020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200770611793920).
111021220120020 is an abundant number, since it is smaller than the sum of its proper divisors (290520003467820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111021220120020 is a wasteful number, since it uses less digits than its factorization.
111021220120020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11526583 (or 11526581 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 111021220120020 its reverse (20021022120111), we get a palindrome (131042242240131).
The spelling of 111021220120020 in words is "one hundred eleven trillion, twenty-one billion, two hundred twenty million, one hundred twenty thousand, twenty".
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