Search a number
-
+
111022000111102 = 255511000055551
BaseRepresentation
bin11001001111100101010010…
…111000001111110111111110
3112120002121012002001122110211
4121033211102320033313332
5104022441024012023402
61032042445221023034
732246034442236313
oct3117452270176776
9476077162048424
10111022000111102
11324141907a8193
1210550983254a7a
1349c443942a702
141d5b6ca156d0a
15cc7e0c5ca4d7
hex64f952e0fdfe

111022000111102 has 4 divisors (see below), whose sum is σ = 166533000166656. Its totient is φ = 55511000055550.

The previous prime is 111022000111091. The next prime is 111022000111123. The reversal of 111022000111102 is 201111000220111.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1110220001111023 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27755500027774 + ... + 27755500027777.

It is an arithmetic number, because the mean of its divisors is an integer number (41633250041664).

Almost surely, 2111022000111102 is an apocalyptic number.

111022000111102 is a deficient number, since it is larger than the sum of its proper divisors (55511000055554).

111022000111102 is an equidigital number, since it uses as much as digits as its factorization.

111022000111102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55511000055553.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 111022000111102 its reverse (201111000220111), we get a palindrome (312133000331213).

The spelling of 111022000111102 in words is "one hundred eleven trillion, twenty-two billion, one hundred eleven thousand, one hundred two".

Divisors: 1 2 55511000055551 111022000111102