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11102210113 is a prime number
BaseRepresentation
bin10100101011011111…
…00100100001000001
31001122201202201011011
422111233210201001
5140214131210423
65033354520521
7542060141341
oct122557444101
931581681134
1011102210113
1147879a9865
12219a136141
13107c1630c7
147746b8d21
1544ea2db0d
hex295be4841

11102210113 has 2 divisors, whose sum is σ = 11102210114. Its totient is φ = 11102210112.

The previous prime is 11102210083. The next prime is 11102210117. The reversal of 11102210113 is 31101220111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10159228849 + 942981264 = 100793^2 + 30708^2 .

It is a cyclic number.

It is not a de Polignac number, because 11102210113 - 25 = 11102210081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11102210093 and 11102210102.

It is not a weakly prime, because it can be changed into another prime (11102210117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551105056 + 5551105057.

It is an arithmetic number, because the mean of its divisors is an integer number (5551105057).

Almost surely, 211102210113 is an apocalyptic number.

It is an amenable number.

11102210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11102210113 is an equidigital number, since it uses as much as digits as its factorization.

11102210113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 11102210113 its reverse (31101220111), we get a palindrome (42203430224).

The spelling of 11102210113 in words is "eleven billion, one hundred two million, two hundred ten thousand, one hundred thirteen".