Base | Representation |
---|---|
bin | 1010000110001111000100… |
… | …1001001110011000101111 |
3 | 1110022100211021112210121120 |
4 | 2201203301021032120233 |
5 | 2423344342223021033 |
6 | 35340144343432023 |
7 | 2224052613210333 |
oct | 241436111163057 |
9 | 43270737483546 |
10 | 11102241220143 |
11 | 35a0485808967 |
12 | 12b3832155613 |
13 | 626c24368158 |
14 | 2a54cc1237c3 |
15 | 143bdc5541b3 |
hex | a18f124e62f |
11102241220143 has 32 divisors (see below), whose sum is σ = 15664207060992. Its totient is φ = 6983121196800.
The previous prime is 11102241220139. The next prime is 11102241220157. The reversal of 11102241220143 is 34102214220111.
It is not a de Polignac number, because 11102241220143 - 22 = 11102241220139 is a prime.
It is a super-2 number, since 2×111022412201432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11102241220163) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4402821 + ... + 6448977.
It is an arithmetic number, because the mean of its divisors is an integer number (489506470656).
Almost surely, 211102241220143 is an apocalyptic number.
11102241220143 is a deficient number, since it is larger than the sum of its proper divisors (4561965840849).
11102241220143 is a wasteful number, since it uses less digits than its factorization.
11102241220143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2047655.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 11102241220143 its reverse (34102214220111), we get a palindrome (45204455440254).
The spelling of 11102241220143 in words is "eleven trillion, one hundred two billion, two hundred forty-one million, two hundred twenty thousand, one hundred forty-three".
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