Base | Representation |
---|---|
bin | 10100101011100101… |
… | …01100001101000011 |
3 | 1001122210022021010120 |
4 | 22111302230031003 |
5 | 140214333344120 |
6 | 5033424231323 |
7 | 542100116061 |
oct | 122562541503 |
9 | 31583267116 |
10 | 11103028035 |
11 | 4788408330 |
12 | 219a46b543 |
13 | 107c38b498 |
14 | 77484d031 |
15 | 44eb41140 |
hex | 295cac343 |
11103028035 has 32 divisors (see below), whose sum is σ = 19745503488. Its totient is φ = 5281710720.
The previous prime is 11103028021. The next prime is 11103028093. The reversal of 11103028035 is 53082030111.
It is not a de Polignac number, because 11103028035 - 25 = 11103028003 is a prime.
It is a super-2 number, since 2×111030280352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11103027996 and 11103028014.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 626077 + ... + 643566.
It is an arithmetic number, because the mean of its divisors is an integer number (617046984).
Almost surely, 211103028035 is an apocalyptic number.
11103028035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11103028035 is a deficient number, since it is larger than the sum of its proper divisors (8642475453).
11103028035 is a wasteful number, since it uses less digits than its factorization.
11103028035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1269715.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 11103028035 its reverse (53082030111), we get a palindrome (64185058146).
The spelling of 11103028035 in words is "eleven billion, one hundred three million, twenty-eight thousand, thirty-five".
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