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11103098108797 is a prime number
BaseRepresentation
bin1010000110010010010000…
…1101111111101101111101
31110022110000222221020212101
42201210210031333231331
52423403121103440142
635340405353505101
72224113056512102
oct241444415775575
943273028836771
1011103098108797
1135a0885475002
1212b3a31112191
1362702ca48a66
142a556dc5aaa9
15143c3c8b70b7
hexa192437fb7d

11103098108797 has 2 divisors, whose sum is σ = 11103098108798. Its totient is φ = 11103098108796.

The previous prime is 11103098108779. The next prime is 11103098108833. The reversal of 11103098108797 is 79780189030111.

Together with previous prime (11103098108779) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11098632394521 + 4465714276 = 3331461^2 + 66826^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11103098108797 is a prime.

It is a super-2 number, since 2×111030981087972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11103098108717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551549054398 + 5551549054399.

It is an arithmetic number, because the mean of its divisors is an integer number (5551549054399).

Almost surely, 211103098108797 is an apocalyptic number.

It is an amenable number.

11103098108797 is a deficient number, since it is larger than the sum of its proper divisors (1).

11103098108797 is an equidigital number, since it uses as much as digits as its factorization.

11103098108797 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 762048, while the sum is 55.

The spelling of 11103098108797 in words is "eleven trillion, one hundred three billion, ninety-eight million, one hundred eight thousand, seven hundred ninety-seven".