Base | Representation |
---|---|
bin | 1010000110010010010110… |
… | …1110001011111000010111 |
3 | 1110022110002202101100020001 |
4 | 2201210211232023320113 |
5 | 2423403144032340224 |
6 | 35340412054152131 |
7 | 2224113514033066 |
oct | 241444556137027 |
9 | 43273082340201 |
10 | 11103123324439 |
11 | 35a0898727983 |
12 | 12b3a39652647 |
13 | 627035037163 |
14 | 2a55733421dd |
15 | 143c3ebe8544 |
hex | a1925b8be17 |
11103123324439 has 2 divisors, whose sum is σ = 11103123324440. Its totient is φ = 11103123324438.
The previous prime is 11103123324431. The next prime is 11103123324511. The reversal of 11103123324439 is 93442332130111.
11103123324439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11103123324439 - 23 = 11103123324431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11103123324398 and 11103123324407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11103123324431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551561662219 + 5551561662220.
It is an arithmetic number, because the mean of its divisors is an integer number (5551561662220).
Almost surely, 211103123324439 is an apocalyptic number.
11103123324439 is a deficient number, since it is larger than the sum of its proper divisors (1).
11103123324439 is an equidigital number, since it uses as much as digits as its factorization.
11103123324439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 37.
The spelling of 11103123324439 in words is "eleven trillion, one hundred three billion, one hundred twenty-three million, three hundred twenty-four thousand, four hundred thirty-nine".
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