Base | Representation |
---|---|
bin | 10000001010000100011… |
… | …011010010111101001101 |
3 | 10221010221100012021100212 |
4 | 100022010123102331031 |
5 | 121142420231413123 |
6 | 2210024145532205 |
7 | 143134563263312 |
oct | 20120433227515 |
9 | 3833840167325 |
10 | 1110323310413 |
11 | 398981620999 |
12 | 15b231044065 |
13 | 8091a765685 |
14 | 3ba5054ad09 |
15 | 1dd36e24878 |
hex | 102846d2f4d |
1110323310413 has 2 divisors, whose sum is σ = 1110323310414. Its totient is φ = 1110323310412.
The previous prime is 1110323310331. The next prime is 1110323310431. The reversal of 1110323310413 is 3140133230111.
Together with next prime (1110323310431) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 785985087364 + 324338223049 = 886558^2 + 569507^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110323310413 - 218 = 1110323048269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110323310433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555161655206 + 555161655207.
It is an arithmetic number, because the mean of its divisors is an integer number (555161655207).
Almost surely, 21110323310413 is an apocalyptic number.
It is an amenable number.
1110323310413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110323310413 is an equidigital number, since it uses as much as digits as its factorization.
1110323310413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1110323310413 its reverse (3140133230111), we get a palindrome (4250456540524).
The spelling of 1110323310413 in words is "one trillion, one hundred ten billion, three hundred twenty-three million, three hundred ten thousand, four hundred thirteen".
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