1110330004013 has 2 divisors, whose sum is σ = 1110330004014. Its totient is φ = 1110330004012.

The previous prime is 1110330003989. The next prime is 1110330004019. The reversal of 1110330004013 is 3104000330111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 905082044164 + 205247959849 = 951358^2 + 453043^2 .

It is an emirp because it is prime and its reverse (3104000330111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1110330004013 - 2¹⁶ = 1110329938477 is a prime.

It is a super-2 number, since 2×1110330004013² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1110330003982 and 1110330004000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110330004019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555165002006 + 555165002007.

It is an arithmetic number, because the mean of its divisors is an integer number (555165002007).

Almost surely, 2^{1110330004013} is an apocalyptic number.

It is an amenable number.

1110330004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110330004013 is an equidigital number, since it uses as much as digits as its factorization.

1110330004013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1110330004013 its reverse (3104000330111), we get a palindrome (4214330334124).

The spelling of 1110330004013 in words is "one trillion, one hundred ten billion, three hundred thirty million, four thousand, thirteen".