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111033011132 = 22171632838399
BaseRepresentation
bin110011101101000010…
…1010100101110111100
3101121121002012101020122
41213122011110232330
53304343422324012
6123001410434112
711010334010501
oct1473205245674
9347532171218
10111033011132
11430a827071a
1219628892938
13a6165247b4
1455344854a8
152d4cb49e72
hex19da154bbc

111033011132 has 12 divisors (see below), whose sum is σ = 205737638400. Its totient is φ = 52250828736.

The previous prime is 111033011119. The next prime is 111033011153. The reversal of 111033011132 is 231110330111.

It is a super-2 number, since 2×1110330111322 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a self number, because there is not a number n which added to its sum of digits gives 111033011132.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 816419132 + ... + 816419267.

It is an arithmetic number, because the mean of its divisors is an integer number (17144803200).

Almost surely, 2111033011132 is an apocalyptic number.

It is an amenable number.

111033011132 is a deficient number, since it is larger than the sum of its proper divisors (94704627268).

111033011132 is a wasteful number, since it uses less digits than its factorization.

111033011132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1632838420 (or 1632838418 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 111033011132 its reverse (231110330111), we get a palindrome (342143341243).

The spelling of 111033011132 in words is "one hundred eleven billion, thirty-three million, eleven thousand, one hundred thirty-two".

Divisors: 1 2 4 17 34 68 1632838399 3265676798 6531353596 27758252783 55516505566 111033011132