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111034345364507 is a prime number
BaseRepresentation
bin11001001111110000110010…
…101101101001110000011011
3112120010210001102211111110102
4121033300302231221300123
5104023141314403131012
61032052250222410015
732246652405200615
oct3117606255516033
9476123042744412
10111034345364507
1132419446331854
121055324973090b
1349c5655c75a96
141d5c13b967db5
15cc83d12e82c2
hex64fc32b69c1b

111034345364507 has 2 divisors, whose sum is σ = 111034345364508. Its totient is φ = 111034345364506.

The previous prime is 111034345364491. The next prime is 111034345364561. The reversal of 111034345364507 is 705463543430111.

It is a weak prime.

It is an emirp because it is prime and its reverse (705463543430111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111034345364507 - 24 = 111034345364491 is a prime.

It is not a weakly prime, because it can be changed into another prime (111034345664507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55517172682253 + 55517172682254.

It is an arithmetic number, because the mean of its divisors is an integer number (55517172682254).

Almost surely, 2111034345364507 is an apocalyptic number.

111034345364507 is a deficient number, since it is larger than the sum of its proper divisors (1).

111034345364507 is an equidigital number, since it uses as much as digits as its factorization.

111034345364507 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1814400, while the sum is 47.

Adding to 111034345364507 its reverse (705463543430111), we get a palindrome (816497888794618).

The spelling of 111034345364507 in words is "one hundred eleven trillion, thirty-four billion, three hundred forty-five million, three hundred sixty-four thousand, five hundred seven".