Base | Representation |
---|---|
bin | 1010000110010101010101… |
… | …0101101010010011110111 |
3 | 1110022112011102121112000012 |
4 | 2201211111111222103313 |
5 | 2423411313040424342 |
6 | 35341023233010435 |
7 | 2224142354262536 |
oct | 241452525522367 |
9 | 43275142545005 |
10 | 11103922201847 |
11 | 35a1168671342 |
12 | 12b40210b3a1b |
13 | 6271316b6097 |
14 | 2a560b49831d |
15 | 143c89decb82 |
hex | a195556a4f7 |
11103922201847 has 2 divisors, whose sum is σ = 11103922201848. Its totient is φ = 11103922201846.
The previous prime is 11103922201819. The next prime is 11103922201913. The reversal of 11103922201847 is 74810222930111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11103922201847 - 210 = 11103922200823 is a prime.
It is a super-2 number, since 2×111039222018472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11103922206847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551961100923 + 5551961100924.
It is an arithmetic number, because the mean of its divisors is an integer number (5551961100924).
Almost surely, 211103922201847 is an apocalyptic number.
11103922201847 is a deficient number, since it is larger than the sum of its proper divisors (1).
11103922201847 is an equidigital number, since it uses as much as digits as its factorization.
11103922201847 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 41.
The spelling of 11103922201847 in words is "eleven trillion, one hundred three billion, nine hundred twenty-two million, two hundred one thousand, eight hundred forty-seven".
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