111041113 has 2 divisors, whose sum is σ = 111041114. Its totient is φ = 111041112.

The previous prime is 111041081. The next prime is 111041131. The reversal of 111041113 is 311140111.

It is a happy number.

Together with next prime (111041131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107495424 + 3545689 = 10368^2 + 1883^2 .

It is an emirp because it is prime and its reverse (311140111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111041113 - 2⁵ = 111041081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111041093 and 111041102.

It is not a weakly prime, because it can be changed into another prime (111041143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55520556 + 55520557.

It is an arithmetic number, because the mean of its divisors is an integer number (55520557).

Almost surely, 2^111041113 is an apocalyptic number.

It is an amenable number.

111041113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111041113 is an equidigital number, since it uses as much as digits as its factorization.

111041113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 111041113 is about 10537.6047088511. The cubic root of 111041113 is about 480.6488808161.

Adding to 111041113 its reverse (311140111), we get a palindrome (422181224).

The spelling of 111041113 in words is "one hundred eleven million, forty-one thousand, one hundred thirteen".