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1110412244113 is a prime number
BaseRepresentation
bin10000001010001001101…
…110100011010010010001
310221011011112112120110121
4100022021232203102101
5121143111013302423
62210041044030241
7143140023225244
oct20121156432221
93834145476417
101110412244113
11398a17844117
1215b256992381
1380933003173
143ba5c29b25b
151dd3eb4045d
hex10289ba3491

1110412244113 has 2 divisors, whose sum is σ = 1110412244114. Its totient is φ = 1110412244112.

The previous prime is 1110412244099. The next prime is 1110412244131. The reversal of 1110412244113 is 3114422140111.

Together with next prime (1110412244131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1110256293969 + 155950144 = 1053687^2 + 12488^2 .

It is a cyclic number.

It is not a de Polignac number, because 1110412244113 - 225 = 1110378689681 is a prime.

It is not a weakly prime, because it can be changed into another prime (1110412244143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555206122056 + 555206122057.

It is an arithmetic number, because the mean of its divisors is an integer number (555206122057).

Almost surely, 21110412244113 is an apocalyptic number.

It is an amenable number.

1110412244113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110412244113 is an equidigital number, since it uses as much as digits as its factorization.

1110412244113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1110412244113 its reverse (3114422140111), we get a palindrome (4224834384224).

The spelling of 1110412244113 in words is "one trillion, one hundred ten billion, four hundred twelve million, two hundred forty-four thousand, one hundred thirteen".