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1110413343341 is a prime number
BaseRepresentation
bin10000001010001001110…
…010101111101001101101
310221011011121121102022202
4100022021302233221231
5121143111303441331
62210041123351245
7143140035454061
oct20121162575155
93834147542282
101110413343341
11398a18424a75
1215b257222525
13809332c95b3
143ba5c4a5aa1
151dd3ecaaecb
hex10289cafa6d

1110413343341 has 2 divisors, whose sum is σ = 1110413343342. Its totient is φ = 1110413343340.

The previous prime is 1110413343301. The next prime is 1110413343349. The reversal of 1110413343341 is 1433433140111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 697260070441 + 413153272900 = 835021^2 + 642770^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1110413343341 is a prime.

It is a super-3 number, since 3×11104133433413 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110413343349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555206671670 + 555206671671.

It is an arithmetic number, because the mean of its divisors is an integer number (555206671671).

Almost surely, 21110413343341 is an apocalyptic number.

It is an amenable number.

1110413343341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110413343341 is an equidigital number, since it uses as much as digits as its factorization.

1110413343341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1110413343341 its reverse (1433433140111), we get a palindrome (2543846483452).

The spelling of 1110413343341 in words is "one trillion, one hundred ten billion, four hundred thirteen million, three hundred forty-three thousand, three hundred forty-one".