Base | Representation |
---|---|
bin | 10000001010001001110… |
… | …110011110010111100111 |
3 | 10221011011200110002121001 |
4 | 100022021312132113213 |
5 | 121143112031234002 |
6 | 2210041200334131 |
7 | 143140046665546 |
oct | 20121166362747 |
9 | 3834150402531 |
10 | 1110414321127 |
11 | 398a18a32661 |
12 | 15b257614347 |
13 | 8093357c677 |
14 | 3ba5c67c15d |
15 | 1dd3ee00a87 |
hex | 10289d9e5e7 |
1110414321127 has 2 divisors, whose sum is σ = 1110414321128. Its totient is φ = 1110414321126.
The previous prime is 1110414321031. The next prime is 1110414321161. The reversal of 1110414321127 is 7211234140111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1110414321127 - 239 = 560658507239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1110414321095 and 1110414321104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110414324127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555207160563 + 555207160564.
It is an arithmetic number, because the mean of its divisors is an integer number (555207160564).
Almost surely, 21110414321127 is an apocalyptic number.
1110414321127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110414321127 is an equidigital number, since it uses as much as digits as its factorization.
1110414321127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 1110414321127 its reverse (7211234140111), we get a palindrome (8321648461238).
The spelling of 1110414321127 in words is "one trillion, one hundred ten billion, four hundred fourteen million, three hundred twenty-one thousand, one hundred twenty-seven".
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