Base | Representation |
---|---|
bin | 11001001111111000001011… |
… | …001100001011011000000011 |
3 | 112120011112111212121002122111 |
4 | 121033320023030023120003 |
5 | 104023304033141244413 |
6 | 1032100040550320151 |
7 | 32250353010245563 |
oct | 3117701314133003 |
9 | 476145455532574 |
10 | 111042272212483 |
11 | 32421843885a87 |
12 | 105548a0359057 |
13 | 49c631a2b5781 |
14 | 1d5c69062cda3 |
15 | cc86e7193d3d |
hex | 64fe0b30b603 |
111042272212483 has 2 divisors, whose sum is σ = 111042272212484. Its totient is φ = 111042272212482.
The previous prime is 111042272212481. The next prime is 111042272212517. The reversal of 111042272212483 is 384212272240111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111042272212483 - 21 = 111042272212481 is a prime.
It is a super-2 number, since 2×1110422722124832 (a number of 29 digits) contains 22 as substring.
Together with 111042272212481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (111042272212481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55521136106241 + 55521136106242.
It is an arithmetic number, because the mean of its divisors is an integer number (55521136106242).
Almost surely, 2111042272212483 is an apocalyptic number.
111042272212483 is a deficient number, since it is larger than the sum of its proper divisors (1).
111042272212483 is an equidigital number, since it uses as much as digits as its factorization.
111042272212483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 40.
The spelling of 111042272212483 in words is "one hundred eleven trillion, forty-two billion, two hundred seventy-two million, two hundred twelve thousand, four hundred eighty-three".
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