11104342013131 has 2 divisors, whose sum is σ = 11104342013132. Its totient is φ = 11104342013130.

The previous prime is 11104342013111. The next prime is 11104342013143. The reversal of 11104342013131 is 13131024340111.

It is a strong prime.

It is an emirp because it is prime and its reverse (13131024340111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11104342013131 - 2¹¹ = 11104342011083 is a prime.

It is a super-2 number, since 2×11104342013131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11104342013096 and 11104342013105.

It is not a weakly prime, because it can be changed into another prime (11104342013111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552171006565 + 5552171006566.

It is an arithmetic number, because the mean of its divisors is an integer number (5552171006566).

Almost surely, 2^{11104342013131} is an apocalyptic number.

11104342013131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11104342013131 is an equidigital number, since it uses as much as digits as its factorization.

11104342013131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 11104342013131 its reverse (13131024340111), we get a palindrome (24235366353242).

The spelling of 11104342013131 in words is "eleven trillion, one hundred four billion, three hundred forty-two million, thirteen thousand, one hundred thirty-one".