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1110440411131 is a prime number
BaseRepresentation
bin10000001010001011011…
…001111111111111111011
310221011020111112121100111
4100022023121333333323
5121143140221124011
62210043531445151
7143140514520652
oct20121331777773
93834214477314
101110440411131
11398a31732447
1215b2642b67b7
1380938ab5a3c
143ba61d10199
151dd42356121
hex1028b67fffb

1110440411131 has 2 divisors, whose sum is σ = 1110440411132. Its totient is φ = 1110440411130.

The previous prime is 1110440411089. The next prime is 1110440411153. The reversal of 1110440411131 is 1311140440111.

It is an a-pointer prime, because the next prime (1110440411153) can be obtained adding 1110440411131 to its sum of digits (22).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1110440411131 - 239 = 560684597243 is a prime.

It is a super-2 number, since 2×11104404111312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1110440415131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555220205565 + 555220205566.

It is an arithmetic number, because the mean of its divisors is an integer number (555220205566).

Almost surely, 21110440411131 is an apocalyptic number.

1110440411131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110440411131 is an equidigital number, since it uses as much as digits as its factorization.

1110440411131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 1110440411131 its reverse (1311140440111), we get a palindrome (2421580851242).

The spelling of 1110440411131 in words is "one trillion, one hundred ten billion, four hundred forty million, four hundred eleven thousand, one hundred thirty-one".