Base | Representation |
---|---|
bin | 110011101101010111… |
… | …1101100110111110011 |
3 | 101121121212002202211002 |
4 | 1213122233230313303 |
5 | 3304404243320201 |
6 | 123002444512215 |
7 | 11010530306144 |
oct | 1473257546763 |
9 | 347555082732 |
10 | 111044120051 |
11 | 43103568a47 |
12 | 1963054b66b |
13 | a618914017 |
14 | 5535b37acb |
15 | 2d4dae176b |
hex | 19dabecdf3 |
111044120051 has 2 divisors, whose sum is σ = 111044120052. Its totient is φ = 111044120050.
The previous prime is 111044120041. The next prime is 111044120053. The reversal of 111044120051 is 150021440111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111044120051 - 26 = 111044119987 is a prime.
Together with 111044120053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111044120053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55522060025 + 55522060026.
It is an arithmetic number, because the mean of its divisors is an integer number (55522060026).
Almost surely, 2111044120051 is an apocalyptic number.
111044120051 is a deficient number, since it is larger than the sum of its proper divisors (1).
111044120051 is an equidigital number, since it uses as much as digits as its factorization.
111044120051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 160, while the sum is 20.
Adding to 111044120051 its reverse (150021440111), we get a palindrome (261065560162).
The spelling of 111044120051 in words is "one hundred eleven billion, forty-four million, one hundred twenty thousand, fifty-one".
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