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11105454497 is a prime number
BaseRepresentation
bin10100101011110111…
…11100100110100001
31001122221212112121112
422111323330212201
5140220444020442
65033552233105
7542126543234
oct122573744641
931587775545
1011105454497
114789815375
12219b23b795
13107ca2aa67
14774cc141b
1544ee70082
hex295efc9a1

11105454497 has 2 divisors, whose sum is σ = 11105454498. Its totient is φ = 11105454496.

The previous prime is 11105454433. The next prime is 11105454499. The reversal of 11105454497 is 79445450111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7856340496 + 3249114001 = 88636^2 + 57001^2 .

It is a cyclic number.

It is not a de Polignac number, because 11105454497 - 26 = 11105454433 is a prime.

It is a super-2 number, since 2×111054544972 (a number of 21 digits) contains 22 as substring.

Together with 11105454499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11105454499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552727248 + 5552727249.

It is an arithmetic number, because the mean of its divisors is an integer number (5552727249).

Almost surely, 211105454497 is an apocalyptic number.

It is an amenable number.

11105454497 is a deficient number, since it is larger than the sum of its proper divisors (1).

11105454497 is an equidigital number, since it uses as much as digits as its factorization.

11105454497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 41.

The spelling of 11105454497 in words is "eleven billion, one hundred five million, four hundred fifty-four thousand, four hundred ninety-seven".