Base | Representation |
---|---|
bin | 10000001010101000110… |
… | …100011110100011010011 |
3 | 10221012111220002222212011 |
4 | 100022220310132203103 |
5 | 121200143034010113 |
6 | 2210204520443351 |
7 | 143155656161416 |
oct | 20125064364323 |
9 | 3835456088764 |
10 | 1110933891283 |
11 | 399165246387 |
12 | 15b381619557 |
13 | 809b70c7328 |
14 | 3baab689b7d |
15 | 1dd7083263d |
hex | 102a8d1e8d3 |
1110933891283 has 2 divisors, whose sum is σ = 1110933891284. Its totient is φ = 1110933891282.
The previous prime is 1110933891281. The next prime is 1110933891317. The reversal of 1110933891283 is 3821983390111.
It is a weak prime.
It is an emirp because it is prime and its reverse (3821983390111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1110933891283 - 21 = 1110933891281 is a prime.
It is a super-2 number, since 2×11109338912832 (a number of 25 digits) contains 22 as substring.
Together with 1110933891281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1110933891281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555466945641 + 555466945642.
It is an arithmetic number, because the mean of its divisors is an integer number (555466945642).
Almost surely, 21110933891283 is an apocalyptic number.
1110933891283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110933891283 is an equidigital number, since it uses as much as digits as its factorization.
1110933891283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 49.
The spelling of 1110933891283 in words is "one trillion, one hundred ten billion, nine hundred thirty-three million, eight hundred ninety-one thousand, two hundred eighty-three".
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