Base | Representation |
---|---|
bin | 10100101100011010… |
… | …10000101111000101 |
3 | 1001200021102010211112 |
4 | 22112031100233011 |
5 | 140223124242123 |
6 | 5034233414405 |
7 | 542213246231 |
oct | 122615205705 |
9 | 31607363745 |
10 | 11109993413 |
11 | 4791335542 |
12 | 21a086a405 |
13 | 10809599cc |
14 | 7757435c1 |
15 | 450569d78 |
hex | 296350bc5 |
11109993413 has 2 divisors, whose sum is σ = 11109993414. Its totient is φ = 11109993412.
The previous prime is 11109993371. The next prime is 11109993431. The reversal of 11109993413 is 31439990111.
Together with next prime (11109993431) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8734210849 + 2375782564 = 93457^2 + 48742^2 .
It is a cyclic number.
It is not a de Polignac number, because 11109993413 - 220 = 11108944837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11109993473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5554996706 + 5554996707.
It is an arithmetic number, because the mean of its divisors is an integer number (5554996707).
Almost surely, 211109993413 is an apocalyptic number.
It is an amenable number.
11109993413 is a deficient number, since it is larger than the sum of its proper divisors (1).
11109993413 is an equidigital number, since it uses as much as digits as its factorization.
11109993413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 41.
The spelling of 11109993413 in words is "eleven billion, one hundred nine million, nine hundred ninety-three thousand, four hundred thirteen".
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