Base | Representation |
---|---|
bin | 10000001010101100110… |
… | …100011110100011010011 |
3 | 10221012200120101110220122 |
4 | 100022230310132203103 |
5 | 121200312224001042 |
6 | 2210215315100455 |
7 | 143160432454163 |
oct | 20125464364323 |
9 | 3835616343818 |
10 | 1111001000147 |
11 | 39919a112255 |
12 | 15b39bba172b |
13 | 809c7c92c0c |
14 | 3bab65585a3 |
15 | 1dd7668b7d2 |
hex | 102acd1e8d3 |
1111001000147 has 2 divisors, whose sum is σ = 1111001000148. Its totient is φ = 1111001000146.
The previous prime is 1111001000101. The next prime is 1111001000173. The reversal of 1111001000147 is 7410001001111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1111001000147 - 226 = 1110933891283 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111001000647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555500500073 + 555500500074.
It is an arithmetic number, because the mean of its divisors is an integer number (555500500074).
Almost surely, 21111001000147 is an apocalyptic number.
1111001000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111001000147 is an equidigital number, since it uses as much as digits as its factorization.
1111001000147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 1111001000147 its reverse (7410001001111), we get a palindrome (8521002001258).
The spelling of 1111001000147 in words is "one trillion, one hundred eleven billion, one million, one hundred forty-seven", and thus it is an aban number.
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