1111001001401 has 2 divisors, whose sum is σ = 1111001001402. Its totient is φ = 1111001001400.

The previous prime is 1111001001389. The next prime is 1111001001421. The reversal of 1111001001401 is 1041001001111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1002151155625 + 108849845776 = 1001075^2 + 329924^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111001001401 is a prime.

It is a super-2 number, since 2×1111001001401² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1111001001421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555500500700 + 555500500701.

It is an arithmetic number, because the mean of its divisors is an integer number (555500500701).

Almost surely, 2^{1111001001401} is an apocalyptic number.

It is an amenable number.

1111001001401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111001001401 is an equidigital number, since it uses as much as digits as its factorization.

1111001001401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1111001001401 its reverse (1041001001111), we get a palindrome (2152002002512).

The spelling of 1111001001401 in words is "one trillion, one hundred eleven billion, one million, one thousand, four hundred one".