Base | Representation |
---|---|
bin | 11001010000101110001000… |
… | …000101001111001110110000 |
3 | 112120101002001002221022111220 |
4 | 121100232020011033032300 |
5 | 104030231203220320422 |
6 | 1032142421145305040 |
7 | 32254503402321552 |
oct | 3120561005171660 |
9 | 476332032838456 |
10 | 111100202120112 |
11 | 324443707a1aa7 |
12 | 10563b68a95180 |
13 | 49cb91cbc6a1a |
14 | 1d613c81bd4d2 |
15 | cc9e87cdae5c |
hex | 650b8814f3b0 |
111100202120112 has 40 divisors (see below), whose sum is σ = 287931713571840. Its totient is φ = 36914322242880.
The previous prime is 111100202120111. The next prime is 111100202120113. The reversal of 111100202120112 is 211021202001111.
It is a happy number.
111100202120112 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (111100202120111) and next prime (111100202120113).
It is a super-2 number, since 2×1111002021201122 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111100202120091 and 111100202120100.
It is not an unprimeable number, because it can be changed into a prime (111100202120111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3721186912 + ... + 3721216767.
It is an arithmetic number, because the mean of its divisors is an integer number (7198292839296).
Almost surely, 2111100202120112 is an apocalyptic number.
111100202120112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
111100202120112 is an abundant number, since it is smaller than the sum of its proper divisors (176831511451728).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111100202120112 is a wasteful number, since it uses less digits than its factorization.
111100202120112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7442404001 (or 7442403995 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 111100202120112 its reverse (211021202001111), we get a palindrome (322121404121223).
The spelling of 111100202120112 in words is "one hundred eleven trillion, one hundred billion, two hundred two million, one hundred twenty thousand, one hundred twelve".
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