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11110041121 is a prime number
BaseRepresentation
bin10100101100011010…
…11100011000100001
31001200021111120021111
422112031130120201
5140223132303441
65034234423321
7542213535304
oct122615343041
931607446244
1011110041121
114791368373
1221a0891b41
13108097563a
14775756b3b
15450579081
hex29635c621

11110041121 has 2 divisors, whose sum is σ = 11110041122. Its totient is φ = 11110041120.

The previous prime is 11110041119. The next prime is 11110041139. The reversal of 11110041121 is 12114001111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11047061025 + 62980096 = 105105^2 + 7936^2 .

It is a cyclic number.

It is not a de Polignac number, because 11110041121 - 21 = 11110041119 is a prime.

It is a super-3 number, since 3×111100411213 (a number of 31 digits) contains 333 as substring.

Together with 11110041119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11110041721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555020560 + 5555020561.

It is an arithmetic number, because the mean of its divisors is an integer number (5555020561).

Almost surely, 211110041121 is an apocalyptic number.

It is an amenable number.

11110041121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110041121 is an equidigital number, since it uses as much as digits as its factorization.

11110041121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 11110041121 its reverse (12114001111), we get a palindrome (23224042232).

The spelling of 11110041121 in words is "eleven billion, one hundred ten million, forty-one thousand, one hundred twenty-one".