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11110100120183 is a prime number
BaseRepresentation
bin1010000110101100010110…
…0100100011001001110111
31110100010002222110021202102
42201223011210203021313
52424011441112321213
635343524243132315
72224451431566341
oct241530544431167
943303088407672
1011110100120183
1135a3848972879
1212b526607409b
136278a75a736c
142a5a35b7c291
15143eec47c158
hexa1ac5923277

11110100120183 has 2 divisors, whose sum is σ = 11110100120184. Its totient is φ = 11110100120182.

The previous prime is 11110100120131. The next prime is 11110100120201. The reversal of 11110100120183 is 38102100101111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11110100120183 is a prime.

It is a super-2 number, since 2×111101001201832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11110100122183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555050060091 + 5555050060092.

It is an arithmetic number, because the mean of its divisors is an integer number (5555050060092).

Almost surely, 211110100120183 is an apocalyptic number.

11110100120183 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110100120183 is an equidigital number, since it uses as much as digits as its factorization.

11110100120183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 20.

Adding to 11110100120183 its reverse (38102100101111), we get a palindrome (49212200221294).

The spelling of 11110100120183 in words is "eleven trillion, one hundred ten billion, one hundred million, one hundred twenty thousand, one hundred eighty-three".