1111012010117 has 2 divisors, whose sum is σ = 1111012010118. Its totient is φ = 1111012010116.

The previous prime is 1111012010063. The next prime is 1111012010153. The reversal of 1111012010117 is 7110102101111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 969937401316 + 141074608801 = 984854^2 + 375599^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111012010117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111012010095 and 1111012010104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111012010177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555506005058 + 555506005059.

It is an arithmetic number, because the mean of its divisors is an integer number (555506005059).

Almost surely, 2^{1111012010117} is an apocalyptic number.

It is an amenable number.

1111012010117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111012010117 is an equidigital number, since it uses as much as digits as its factorization.

1111012010117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 17.

Adding to 1111012010117 its reverse (7110102101111), we get a palindrome (8221114111228).

The spelling of 1111012010117 in words is "one trillion, one hundred eleven billion, twelve million, ten thousand, one hundred seventeen".