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1111012012153 is a prime number
BaseRepresentation
bin10000001010101101011…
…110011111000001111001
310221012201100002221112201
4100022231132133001321
5121200323033342103
62210220351110201
7143160625200151
oct20125536370171
93835640087481
101111012012153
113991a535378a
1215b3a3812361
13809ca34a2b4
143bab7bc3761
151dd7761451d
hex102ad79f079

1111012012153 has 2 divisors, whose sum is σ = 1111012012154. Its totient is φ = 1111012012152.

The previous prime is 1111012011947. The next prime is 1111012012163. The reversal of 1111012012153 is 3512102101111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 884828066409 + 226183945744 = 940653^2 + 475588^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111012012153 - 217 = 1111011881081 is a prime.

It is a super-2 number, since 2×11110120121532 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1111012012153.

It is not a weakly prime, because it can be changed into another prime (1111012012163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555506006076 + 555506006077.

It is an arithmetic number, because the mean of its divisors is an integer number (555506006077).

Almost surely, 21111012012153 is an apocalyptic number.

It is an amenable number.

1111012012153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111012012153 is an equidigital number, since it uses as much as digits as its factorization.

1111012012153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 1111012012153 its reverse (3512102101111), we get a palindrome (4623114113264).

The spelling of 1111012012153 in words is "one trillion, one hundred eleven billion, twelve million, twelve thousand, one hundred fifty-three".