Base | Representation |
---|---|
bin | 10000001010101101100… |
… | …010101000110111100111 |
3 | 10221012201102011021012112 |
4 | 100022231202220313213 |
5 | 121200323323213111 |
6 | 2210220430311235 |
7 | 143160640353551 |
oct | 20125542506747 |
9 | 3835642137175 |
10 | 1111013101031 |
11 | 3991a5a27889 |
12 | 15b3a405851b |
13 | 809ca63bac2 |
14 | 3bab7dc84d1 |
15 | 1dd7777be8b |
hex | 102ad8a8de7 |
1111013101031 has 2 divisors, whose sum is σ = 1111013101032. Its totient is φ = 1111013101030.
The previous prime is 1111013101007. The next prime is 1111013101049. The reversal of 1111013101031 is 1301013101111.
It is a strong prime.
It is an emirp because it is prime and its reverse (1301013101111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1111013101031 - 210 = 1111013100007 is a prime.
It is a super-2 number, since 2×11110131010312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1111013100997 and 1111013101015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111013101061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555506550515 + 555506550516.
It is an arithmetic number, because the mean of its divisors is an integer number (555506550516).
Almost surely, 21111013101031 is an apocalyptic number.
1111013101031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111013101031 is an equidigital number, since it uses as much as digits as its factorization.
1111013101031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 14.
Adding to 1111013101031 its reverse (1301013101111), we get a palindrome (2412026202142).
The spelling of 1111013101031 in words is "one trillion, one hundred eleven billion, thirteen million, one hundred one thousand, thirty-one".
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