Base | Representation |
---|---|
bin | 11001010000101111110011… |
… | …111101110010110011011001 |
3 | 112120101020201020202020010002 |
4 | 121100233303331302303121 |
5 | 104030243410044423433 |
6 | 1032143320523502345 |
7 | 32254566301055264 |
oct | 3120576375626331 |
9 | 476336636666102 |
10 | 111102012107993 |
11 | 3244510a458755 |
12 | 105643930879b5 |
13 | 49cbb4aba2c7a |
14 | 1d6151a735cdb |
15 | cca041b689e8 |
hex | 650bf3f72cd9 |
111102012107993 has 2 divisors, whose sum is σ = 111102012107994. Its totient is φ = 111102012107992.
The previous prime is 111102012107941. The next prime is 111102012108023. The reversal of 111102012107993 is 399701210201111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108375012350224 + 2726999757769 = 10410332^2 + 1651363^2 .
It is a cyclic number.
It is not a de Polignac number, because 111102012107993 - 242 = 106703965596889 is a prime.
It is not a weakly prime, because it can be changed into another prime (111102012107293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55551006053996 + 55551006053997.
It is an arithmetic number, because the mean of its divisors is an integer number (55551006053997).
Almost surely, 2111102012107993 is an apocalyptic number.
It is an amenable number.
111102012107993 is a deficient number, since it is larger than the sum of its proper divisors (1).
111102012107993 is an equidigital number, since it uses as much as digits as its factorization.
111102012107993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 38.
The spelling of 111102012107993 in words is "one hundred eleven trillion, one hundred two billion, twelve million, one hundred seven thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •