Base | Representation |
---|---|
bin | 10000001010101101111… |
… | …101101110000100001011 |
3 | 10221012201220111221102211 |
4 | 100022231331232010023 |
5 | 121200332132401303 |
6 | 2210221242405551 |
7 | 143161054612054 |
oct | 20125575560413 |
9 | 3835656457384 |
10 | 1111020200203 |
11 | 3991a9a36571 |
12 | 15b3a65008b7 |
13 | 809cbc561b4 |
14 | 3bab8d1572b |
15 | 1dd781d066d |
hex | 102adf6e10b |
1111020200203 has 2 divisors, whose sum is σ = 1111020200204. Its totient is φ = 1111020200202.
The previous prime is 1111020200189. The next prime is 1111020200233. The reversal of 1111020200203 is 3020020201111.
It is a weak prime.
It is an emirp because it is prime and its reverse (3020020201111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1111020200203 - 225 = 1110986645771 is a prime.
It is a super-2 number, since 2×11110202002032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1111020200233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555510100101 + 555510100102.
It is an arithmetic number, because the mean of its divisors is an integer number (555510100102).
Almost surely, 21111020200203 is an apocalyptic number.
1111020200203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111020200203 is an equidigital number, since it uses as much as digits as its factorization.
1111020200203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1111020200203 its reverse (3020020201111), we get a palindrome (4131040401314).
The spelling of 1111020200203 in words is "one trillion, one hundred eleven billion, twenty million, two hundred thousand, two hundred three".
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