Base | Representation |
---|---|
bin | 11001010000101111111001… |
… | …111010110110100010010011 |
3 | 112120101020222012201021101111 |
4 | 121100233321322312202103 |
5 | 104030244111133001042 |
6 | 1032143334452514151 |
7 | 32254601623121122 |
oct | 3120577172664223 |
9 | 476336865637344 |
10 | 111102112000147 |
11 | 32445160886154 |
12 | 1056440061b957 |
13 | 49cbb657a9658 |
14 | 1d61529ad9ab9 |
15 | cca04a7eb517 |
hex | 650bf9eb6893 |
111102112000147 has 2 divisors, whose sum is σ = 111102112000148. Its totient is φ = 111102112000146.
The previous prime is 111102112000051. The next prime is 111102112000219. The reversal of 111102112000147 is 741000211201111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111102112000147 - 223 = 111102103611539 is a prime.
It is not a weakly prime, because it can be changed into another prime (111102172000147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55551056000073 + 55551056000074.
It is an arithmetic number, because the mean of its divisors is an integer number (55551056000074).
Almost surely, 2111102112000147 is an apocalyptic number.
111102112000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
111102112000147 is an equidigital number, since it uses as much as digits as its factorization.
111102112000147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 111102112000147 its reverse (741000211201111), we get a palindrome (852102323201258).
The spelling of 111102112000147 in words is "one hundred eleven trillion, one hundred two billion, one hundred twelve million, one hundred forty-seven", and thus it is an aban number.
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