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11110211210112 = 273721113153047
BaseRepresentation
bin1010000110101100110000…
…1100010100101110000000
31110100010101201111020111020
42201223030030110232000
52424012203032210422
635343543252145440
72224454251050600
oct241531414245600
943303351436436
1011110211210112
1135a38a5649333
1212b5297308280
136278c4601851
142a5a46818c00
151440070c295c
hexa1acc314b80

11110211210112 has 192 divisors, whose sum is σ = 34333433735040. Its totient is φ = 3174001044480.

The previous prime is 11110211210099. The next prime is 11110211210233. The reversal of 11110211210112 is 21101211201111.

It is a tau number, because it is divible by the number of its divisors (192).

It is a super-2 number, since 2×111102112101122 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11110211210091 and 11110211210100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 209414373 + ... + 209467419.

It is an arithmetic number, because the mean of its divisors is an integer number (178819967370).

Almost surely, 211110211210112 is an apocalyptic number.

11110211210112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11110211210112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17166716867520).

11110211210112 is an abundant number, since it is smaller than the sum of its proper divisors (23223222524928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11110211210112 is a wasteful number, since it uses less digits than its factorization.

11110211210112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64209 (or 64190 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 15.

Adding to 11110211210112 its reverse (21101211201111), we get a palindrome (32211422411223).

Subtracting 11110211210112 from its reverse (21101211201111), we obtain a palindrome (9990999990999).

The spelling of 11110211210112 in words is "eleven trillion, one hundred ten billion, two hundred eleven million, two hundred ten thousand, one hundred twelve".