11110231147 has 2 divisors, whose sum is σ = 11110231148. Its totient is φ = 11110231146.

The previous prime is 11110231091. The next prime is 11110231169. The reversal of 11110231147 is 74113201111.

11110231147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (11110231169) can be obtained adding 11110231147 to its sum of digits (22).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11110231147 - 2¹¹ = 11110229099 is a prime.

It is a super-2 number, since 2×11110231147² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11110234147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555115573 + 5555115574.

It is an arithmetic number, because the mean of its divisors is an integer number (5555115574).

Almost surely, 2^11110231147 is an apocalyptic number.

11110231147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110231147 is an equidigital number, since it uses as much as digits as its factorization.

11110231147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 22.

Adding to 11110231147 its reverse (74113201111), we get a palindrome (85223432258).

The spelling of 11110231147 in words is "eleven billion, one hundred ten million, two hundred thirty-one thousand, one hundred forty-seven".