Base | Representation |
---|---|
bin | 10000001010101110100… |
… | …011100110010101111111 |
3 | 10221012202121012102121211 |
4 | 100022232203212111333 |
5 | 121200342203130142 |
6 | 2210222235305251 |
7 | 143161235200045 |
oct | 20125643462577 |
9 | 3835677172554 |
10 | 1111030130047 |
11 | 3992045a8a52 |
12 | 15b3a98ab227 |
13 | 80a01021b46 |
14 | 3baba37c395 |
15 | 1dd78ee2917 |
hex | 102ae8e657f |
1111030130047 has 2 divisors, whose sum is σ = 1111030130048. Its totient is φ = 1111030130046.
The previous prime is 1111030129921. The next prime is 1111030130051. The reversal of 1111030130047 is 7400310301111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111030130047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111030130647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555515065023 + 555515065024.
It is an arithmetic number, because the mean of its divisors is an integer number (555515065024).
Almost surely, 21111030130047 is an apocalyptic number.
1111030130047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111030130047 is an equidigital number, since it uses as much as digits as its factorization.
1111030130047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 1111030130047 its reverse (7400310301111), we get a palindrome (8511340431158).
The spelling of 1111030130047 in words is "one trillion, one hundred eleven billion, thirty million, one hundred thirty thousand, forty-seven".
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