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1111040130230 = 25111104013023
BaseRepresentation
bin10000001010101111001…
…001101111110010110110
310221012210022000111021222
4100022233021233302312
5121200402233131410
62210223233510342
7143161416200102
oct20125711576266
93835708014258
101111040130230
1139920a209268
1215b3b11123b2
1380a03113804
143babb822902
151dd79d1a955
hex102af26fcb6

1111040130230 has 8 divisors (see below), whose sum is σ = 1999872234432. Its totient is φ = 444416052088.

The previous prime is 1111040130157. The next prime is 1111040130259. The reversal of 1111040130230 is 320310401111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1111040130199 and 1111040130208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55552006502 + ... + 55552006521.

It is an arithmetic number, because the mean of its divisors is an integer number (249984029304).

Almost surely, 21111040130230 is an apocalyptic number.

1111040130230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1111040130230 is a deficient number, since it is larger than the sum of its proper divisors (888832104202).

1111040130230 is a wasteful number, since it uses less digits than its factorization.

1111040130230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111104013030.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1111040130230 its reverse (320310401111), we get a palindrome (1431350531341).

The spelling of 1111040130230 in words is "one trillion, one hundred eleven billion, forty million, one hundred thirty thousand, two hundred thirty".

Divisors: 1 2 5 10 111104013023 222208026046 555520065115 1111040130230