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111104332081 is a prime number
BaseRepresentation
bin110011101111001010…
…1011001000100110001
3101121210001101212012021
41213132111121010301
53310020202111311
6123012435231441
711012161145341
oct1473625310461
9347701355167
10111104332081
1143134554156
1219648748581
13a628236642
14553db2cd21
152d54037171
hex19de559131

111104332081 has 2 divisors, whose sum is σ = 111104332082. Its totient is φ = 111104332080.

The previous prime is 111104332007. The next prime is 111104332123. The reversal of 111104332081 is 180233401111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89844067600 + 21260264481 = 299740^2 + 145809^2 .

It is a cyclic number.

It is not a de Polignac number, because 111104332081 - 223 = 111095943473 is a prime.

It is a super-2 number, since 2×1111043320812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111104332681) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55552166040 + 55552166041.

It is an arithmetic number, because the mean of its divisors is an integer number (55552166041).

Almost surely, 2111104332081 is an apocalyptic number.

It is an amenable number.

111104332081 is a deficient number, since it is larger than the sum of its proper divisors (1).

111104332081 is an equidigital number, since it uses as much as digits as its factorization.

111104332081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 111104332081 its reverse (180233401111), we get a palindrome (291337733192).

The spelling of 111104332081 in words is "one hundred eleven billion, one hundred four million, three hundred thirty-two thousand, eighty-one".