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111106266281 is a prime number
BaseRepresentation
bin110011101111001110…
…0110001010010101001
3101121210012001010102022
41213132130301102221
53310021201010111
6123012544514225
711012213452403
oct1473634612251
9347705033368
10111106266281
114313565536a
121964931b975
13a628762b3a
1455400b3b73
152d542ba2db
hex19de7314a9

111106266281 has 2 divisors, whose sum is σ = 111106266282. Its totient is φ = 111106266280.

The previous prime is 111106266277. The next prime is 111106266283. The reversal of 111106266281 is 182662601111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102016360000 + 9089906281 = 319400^2 + 95341^2 .

It is an emirp because it is prime and its reverse (182662601111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111106266281 - 22 = 111106266277 is a prime.

It is a super-2 number, since 2×1111062662812 (a number of 23 digits) contains 22 as substring.

Together with 111106266283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (111106266283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55553133140 + 55553133141.

It is an arithmetic number, because the mean of its divisors is an integer number (55553133141).

Almost surely, 2111106266281 is an apocalyptic number.

It is an amenable number.

111106266281 is a deficient number, since it is larger than the sum of its proper divisors (1).

111106266281 is an equidigital number, since it uses as much as digits as its factorization.

111106266281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 35.

Adding to 111106266281 its reverse (182662601111), we get a palindrome (293768867392).

The spelling of 111106266281 in words is "one hundred eleven billion, one hundred six million, two hundred sixty-six thousand, two hundred eighty-one".