Base | Representation |
---|---|
bin | 11001010000110111010110… |
… | …000110011110001110101011 |
3 | 112120102000120222102120110211 |
4 | 121100313112012132032223 |
5 | 104030411441324014011 |
6 | 1032151135320521551 |
7 | 32255303611401151 |
oct | 3120672606361653 |
9 | 476360528376424 |
10 | 111110101001131 |
11 | 32448590420901 |
12 | 10565a700202b7 |
13 | 49cc83996b27b |
14 | 1d61a86b3d3d1 |
15 | cca366d72b21 |
hex | 650dd619e3ab |
111110101001131 has 2 divisors, whose sum is σ = 111110101001132. Its totient is φ = 111110101001130.
The previous prime is 111110101001093. The next prime is 111110101001161. The reversal of 111110101001131 is 131100101011111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111110101001131 - 213 = 111110100992939 is a prime.
It is a super-2 number, since 2×1111101010011312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111110101001161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555050500565 + 55555050500566.
It is an arithmetic number, because the mean of its divisors is an integer number (55555050500566).
Almost surely, 2111110101001131 is an apocalyptic number.
111110101001131 is a deficient number, since it is larger than the sum of its proper divisors (1).
111110101001131 is an equidigital number, since it uses as much as digits as its factorization.
111110101001131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3, while the sum is 13.
Adding to 111110101001131 its reverse (131100101011111), we get a palindrome (242210202012242).
The spelling of 111110101001131 in words is "one hundred eleven trillion, one hundred ten billion, one hundred one million, one thousand, one hundred thirty-one".
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