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11111010999997 is a prime number
BaseRepresentation
bin1010000110101111101111…
…0111010001111010111101
31110100012110110102202221211
42201223323313101322331
52424020322303444442
635344154502324421
72224513132130536
oct241537367217275
943305413382854
1011111010999997
1135a4176056307
1212b547b129711
136279c120cbbc
142a5ac0b2b68d
15144052407617
hexa1afbdd1ebd

11111010999997 has 2 divisors, whose sum is σ = 11111010999998. Its totient is φ = 11111010999996.

The previous prime is 11111010999973. The next prime is 11111011000031. The reversal of 11111010999997 is 79999901011111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10702358930916 + 408652069081 = 3271446^2 + 639259^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11111010999997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111010999397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555505499998 + 5555505499999.

It is an arithmetic number, because the mean of its divisors is an integer number (5555505499999).

Almost surely, 211111010999997 is an apocalyptic number.

It is an amenable number.

11111010999997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111010999997 is an equidigital number, since it uses as much as digits as its factorization.

11111010999997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 413343, while the sum is 58.

The spelling of 11111010999997 in words is "eleven trillion, one hundred eleven billion, ten million, nine hundred ninety-nine thousand, nine hundred ninety-seven".