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111110111000957 is a prime number
BaseRepresentation
bin11001010000110111010110…
…101100100111100101111101
3112120102000121200020121122202
4121100313112230213211331
5104030412001404012312
61032151140315121245
732255304062400155
oct3120672654474575
9476360550217582
10111110111000957
1132448596030922
1210565a73443225
1349cc83ba5ca23
141d61a881c3765
15cca367b9a9c2
hex650dd6b2797d

111110111000957 has 2 divisors, whose sum is σ = 111110111000958. Its totient is φ = 111110111000956.

The previous prime is 111110111000921. The next prime is 111110111001017. The reversal of 111110111000957 is 759000111011111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104165273287321 + 6944837713636 = 10206139^2 + 2635306^2 .

It is an emirp because it is prime and its reverse (759000111011111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111110111000957 - 214 = 111110110984573 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111110111000857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555055500478 + 55555055500479.

It is an arithmetic number, because the mean of its divisors is an integer number (55555055500479).

Almost surely, 2111110111000957 is an apocalyptic number.

It is an amenable number.

111110111000957 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110111000957 is an equidigital number, since it uses as much as digits as its factorization.

111110111000957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 315, while the sum is 29.

The spelling of 111110111000957 in words is "one hundred eleven trillion, one hundred ten billion, one hundred eleven million, nine hundred fifty-seven", and thus it is an aban number.