Base | Representation |
---|---|
bin | 1010000110101111101111… |
… | …0111101010100101111101 |
3 | 1110100012110110121220120122 |
4 | 2201223323313222211331 |
5 | 2424020322320213203 |
6 | 35344154504424325 |
7 | 2224513133031263 |
oct | 241537367524575 |
9 | 43305413556518 |
10 | 11111011101053 |
11 | 35a4176115226 |
12 | 12b547b1780a5 |
13 | 6279c1246bb6 |
14 | 2a5ac0b56433 |
15 | 144052427538 |
hex | a1afbdea97d |
11111011101053 has 2 divisors, whose sum is σ = 11111011101054. Its totient is φ = 11111011101052.
The previous prime is 11111011101007. The next prime is 11111011101077. The reversal of 11111011101053 is 35010111011111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9300901868644 + 1810109232409 = 3049738^2 + 1345403^2 .
It is a cyclic number.
It is not a de Polignac number, because 11111011101053 - 212 = 11111011096957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11111011106053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555505550526 + 5555505550527.
It is an arithmetic number, because the mean of its divisors is an integer number (5555505550527).
Almost surely, 211111011101053 is an apocalyptic number.
It is an amenable number.
11111011101053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111011101053 is an equidigital number, since it uses as much as digits as its factorization.
11111011101053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 17.
Adding to 11111011101053 its reverse (35010111011111), we get a palindrome (46121122112164).
The spelling of 11111011101053 in words is "eleven trillion, one hundred eleven billion, eleven million, one hundred one thousand, fifty-three".
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