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11111021230207 is a prime number
BaseRepresentation
bin1010000110101111110001…
…1110010011100001111111
31110100012111011200112011111
42201223330132103201333
52424020332413331312
635344155505502451
72224513315106323
oct241537436234177
943305434615144
1011111021230207
1135a4180903428
1212b5482641a27
136279c3382492
142a5ac2231983
151440532788a7
hexa1afc79387f

11111021230207 has 2 divisors, whose sum is σ = 11111021230208. Its totient is φ = 11111021230206.

The previous prime is 11111021230171. The next prime is 11111021230217. The reversal of 11111021230207 is 70203212011111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11111021230207 - 215 = 11111021197439 is a prime.

It is a super-2 number, since 2×111110212302072 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111021230217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555510615103 + 5555510615104.

It is an arithmetic number, because the mean of its divisors is an integer number (5555510615104).

Almost surely, 211111021230207 is an apocalyptic number.

11111021230207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111021230207 is an equidigital number, since it uses as much as digits as its factorization.

11111021230207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 22.

Adding to 11111021230207 its reverse (70203212011111), we get a palindrome (81314233241318).

The spelling of 11111021230207 in words is "eleven trillion, one hundred eleven billion, twenty-one million, two hundred thirty thousand, two hundred seven".