Base | Representation |
---|---|
bin | 110011101111010110… |
… | …0111110010101111001 |
3 | 101121210111000221020202 |
4 | 1213132230332111321 |
5 | 3310023242422131 |
6 | 123013215531545 |
7 | 11012264533502 |
oct | 1473654762571 |
9 | 347714027222 |
10 | 111110514041 |
11 | 43137a9680a |
12 | 1964a829bb5 |
13 | a6295bc3c7 |
14 | 554089bba9 |
15 | 2d54858bcb |
hex | 19deb3e579 |
111110514041 has 2 divisors, whose sum is σ = 111110514042. Its totient is φ = 111110514040.
The previous prime is 111110514023. The next prime is 111110514043. The reversal of 111110514041 is 140415011111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56356386025 + 54754128016 = 237395^2 + 233996^2 .
It is a cyclic number.
It is not a de Polignac number, because 111110514041 - 230 = 110036772217 is a prime.
It is a Sophie Germain prime.
Together with 111110514043, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (111110514043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555257020 + 55555257021.
It is an arithmetic number, because the mean of its divisors is an integer number (55555257021).
Almost surely, 2111110514041 is an apocalyptic number.
It is an amenable number.
111110514041 is a deficient number, since it is larger than the sum of its proper divisors (1).
111110514041 is an equidigital number, since it uses as much as digits as its factorization.
111110514041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 111110514041 its reverse (140415011111), we get a palindrome (251525525152).
The spelling of 111110514041 in words is "one hundred eleven billion, one hundred ten million, five hundred fourteen thousand, forty-one".
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