Base | Representation |
---|---|
bin | 10000001010110011010… |
… | …100010100010001111011 |
3 | 10221012222011111202021211 |
4 | 100022303110110101323 |
5 | 121201023130304404 |
6 | 2210234211343551 |
7 | 143163225153124 |
oct | 20126324242173 |
9 | 3835864452254 |
10 | 1111110009979 |
11 | 3992456a7a22 |
12 | 15b4105b1bb7 |
13 | 80a1473c688 |
14 | 3bac6c1304b |
15 | 1dd81020b04 |
hex | 102b351447b |
1111110009979 has 2 divisors, whose sum is σ = 1111110009980. Its totient is φ = 1111110009978.
The previous prime is 1111110009973. The next prime is 1111110010019. The reversal of 1111110009979 is 9799000111111.
It is an a-pointer prime, because the next prime (1111110010019) can be obtained adding 1111110009979 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1111110009979 - 233 = 1102520075387 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111110009973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555555004989 + 555555004990.
It is an arithmetic number, because the mean of its divisors is an integer number (555555004990).
Almost surely, 21111110009979 is an apocalyptic number.
1111110009979 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111110009979 is an equidigital number, since it uses as much as digits as its factorization.
1111110009979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5103, while the sum is 40.
The spelling of 1111110009979 in words is "one trillion, one hundred eleven billion, one hundred ten million, nine thousand, nine hundred seventy-nine".
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