111111100000007 has 2 divisors, whose sum is σ = 111111100000008. Its totient is φ = 111111100000006.

The previous prime is 111111099999997. The next prime is 111111100000057. The reversal of 111111100000007 is 700000001111111.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111111100000007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111111099999937 and 111111100000000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111111100000057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555550000003 + 55555550000004.

It is an arithmetic number, because the mean of its divisors is an integer number (55555550000004).

Almost surely, 2^{111111100000007} is an apocalyptic number.

111111100000007 is a deficient number, since it is larger than the sum of its proper divisors (1).

111111100000007 is an equidigital number, since it uses as much as digits as its factorization.

111111100000007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7, while the sum is 14.

Adding to 111111100000007 its reverse (700000001111111), we get a palindrome (811111101111118).

The spelling of 111111100000007 in words is "one hundred eleven trillion, one hundred eleven billion, one hundred million, seven", and thus it is an aban number.