111111102013 has 2 divisors, whose sum is σ = 111111102014. Its totient is φ = 111111102012.

The previous prime is 111111101993. The next prime is 111111102059. The reversal of 111111102013 is 310201111111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86881689049 + 24229412964 = 294757^2 + 155658^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111111102013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111111101984 and 111111102002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111111102413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555551006 + 55555551007.

It is an arithmetic number, because the mean of its divisors is an integer number (55555551007).

Almost surely, 2^111111102013 is an apocalyptic number.

It is an amenable number.

111111102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111111102013 is an equidigital number, since it uses as much as digits as its factorization.

111111102013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 111111102013 its reverse (310201111111), we get a palindrome (421312213124).

The spelling of 111111102013 in words is "one hundred eleven billion, one hundred eleven million, one hundred two thousand, thirteen".