Base | Representation |
---|---|
bin | 1010000110110000001001… |
… | …0111111011000000101011 |
3 | 1110100012202001221201220122 |
4 | 2201230002113323000223 |
5 | 2424021033234021303 |
6 | 35344213403313455 |
7 | 2224515626364023 |
oct | 241540227730053 |
9 | 43305661851818 |
10 | 11111120220203 |
11 | 35a4221775043 |
12 | 12b54ab81b88b |
13 | 627a0aa31343 |
14 | 2a5ad143ca83 |
15 | 14405bccde38 |
hex | a1b025fb02b |
11111120220203 has 2 divisors, whose sum is σ = 11111120220204. Its totient is φ = 11111120220202.
The previous prime is 11111120220169. The next prime is 11111120220217. The reversal of 11111120220203 is 30202202111111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11111120220203 is a prime.
It is a super-6 number, since 6×111111202202036 (a number of 80 digits) contains 666666 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11111120220223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555560110101 + 5555560110102.
It is an arithmetic number, because the mean of its divisors is an integer number (5555560110102).
Almost surely, 211111120220203 is an apocalyptic number.
11111120220203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111120220203 is an equidigital number, since it uses as much as digits as its factorization.
11111120220203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11111120220203 its reverse (30202202111111), we get a palindrome (41313322331314).
The spelling of 11111120220203 in words is "eleven trillion, one hundred eleven billion, one hundred twenty million, two hundred twenty thousand, two hundred three".
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